In a mall that sells blazers, 1000 silver blazers were sold and 10% of the remaining blazers that were sold were blue. Of the leftover, 60% of the blazers sold were gold blazers and the rest were black blazers. Given that the number of black blazers sold was 20% of the total number of blazers sold, how many blue and silver blazers were sold altogether?
10% = ¹⁰₁₀₀ = ¹₁₀
60% = ⁶⁰₁₀₀ = ³₅
20% = ²⁰₁₀₀ = ¹₅

Silver	Blue	Gold	Black
1000	1x5	9x5
		3x9	2x9
4x18			1x18
40 u	5 u	27 u	18 u

The total number of gold and black shirts is the combined repeated identity. Make the total number of gold and black shirts the same. LCM of 9 and 5 is 45.

The number of black shirts is repeated. Make the number of black shirts the same. LCM of 18 and 1 is 18.

Number of silver blazers
= 72 u - 5 u - 27 u
= 40 u

40 u = 1000

1 u = 1000 ÷ 40 = 25

Number of blue and silver blazers
= 5 u + 1000
= (5 x 25) + 1000
= 125 + 1000
= 1125

Answer(s): 1125