Roshel had $1118 less than Luke. Roshel spent
14 of her money and Luke spent
57 of his money. In the end, Luke and Roshel had the same amount of money left. Find the amount of money Luke had at first.
|
Roshel |
Luke |
Difference |
Before |
4x2 = 8 u |
7x3 = 21 u |
13 u |
Change |
- 1x2 = - 2 u |
- 5x3 = - 15 u |
|
After |
3x2 = 6 u |
2x3 = 6 u |
|
Fraction of Roshel's money left
= 1 -
14 =
34 Fraction of Luke's money left
= 1 -
57 =
27Luke and Roshel had the same amount of money in the end. Make the numerators the same. LCM of 3 and 2 is 6.
34 of Roshel's money =
27 of Luke's money
68 of Roshel's money =
621 of Luke's money
Amount that Roshel had at first = 8 u
Amount that Luke had at first = 21 u
Amount that Roshel had less than Luke had at first
= 21 u - 8 u
= 13 u
13 u = 1118
1 u = 1118 ÷ 13 = 86
Amount that Luke had at first
= 21 u
= 21 x 86
= $1806
Answer(s): $1806