Min had $858 less than Fabian. Min spent ¹₇ of her money and Fabian spent ²₃ of his money. In the end, Fabian and Min had the same amount of money left. Find the amount of money Fabian had at first.

	Min	Fabian	Difference
Before	7x1 = 7 u	3x6 = 18 u	11 u
Change	- 1x1 = - 1 u	- 2x6 = - 12 u
After	6x1 = 6 u	1x6 = 6 u

Fraction of Min's money left
= 1 - ¹₇
= ⁶₇

Fraction of Fabian's money left
= 1 - ²₃
= ¹₃

Fabian and Min had the same amount of money in the end. Make the numerators the same. LCM of 6 and 1 is 6.

⁶₇ of Min's money = ¹₃ of Fabian's money
⁶₇ of Min's money = ⁶₁₈ of Fabian's money

Amount that Min had at first = 7 u
Amount that Fabian had at first = 18 u

Amount that Min had less than Fabian had at first
= 18 u - 7 u
= 11 u

11 u = 858

1 u = 858 ÷ 11 = 78

Amount that Fabian had at first
= 18 u
= 18 x 78
= $1404

Answer(s): $1404