Jaslyn had $460 less than Lee. Jaslyn spent ¹₃ of her money and Lee spent ⁴₇ of his money. In the end, Lee and Jaslyn had the same amount of money left. Find the amount of money Lee had at first.

	Jaslyn	Lee	Difference
Before	3x3 = 9 u	7x2 = 14 u	5 u
Change	- 1x3 = - 3 u	- 4x2 = - 8 u
After	2x3 = 6 u	3x2 = 6 u

Fraction of Jaslyn's money left
= 1 - ¹₃
= ²₃

Fraction of Lee's money left
= 1 - ⁴₇
= ³₇

Lee and Jaslyn had the same amount of money in the end. Make the numerators the same. LCM of 2 and 3 is 6.

²₃ of Jaslyn's money = ³₇ of Lee's money
⁶₉ of Jaslyn's money = ⁶₁₄ of Lee's money

Amount that Jaslyn had at first = 9 u
Amount that Lee had at first = 14 u

Amount that Jaslyn had less than Lee had at first
= 14 u - 9 u
= 5 u

5 u = 460

1 u = 460 ÷ 5 = 92

Amount that Lee had at first
= 14 u
= 14 x 92
= $1288

Answer(s): $1288