Abi had $936 less than Cole. Abi spent ¹₇ of her money and Cole spent ³₅ of his money. In the end, Cole and Abi had the same amount of money left. Find the amount of money Cole had at first.

	Abi	Cole	Difference
Before	7x1 = 7 u	5x3 = 15 u	8 u
Change	- 1x1 = - 1 u	- 3x3 = - 9 u
After	6x1 = 6 u	2x3 = 6 u

Fraction of Abi's money left
= 1 - ¹₇
= ⁶₇

Fraction of Cole's money left
= 1 - ³₅
= ²₅

Cole and Abi had the same amount of money in the end. Make the numerators the same. LCM of 6 and 2 is 6.

⁶₇ of Abi's money = ²₅ of Cole's money
⁶₇ of Abi's money = ⁶₁₅ of Cole's money

Amount that Abi had at first = 7 u
Amount that Cole had at first = 15 u

Amount that Abi had less than Cole had at first
= 15 u - 7 u
= 8 u

8 u = 936

1 u = 936 ÷ 8 = 117

Amount that Cole had at first
= 15 u
= 15 x 117
= $1755

Answer(s): $1755