Julie had $603 less than Ahmad. Julie spent
15 of her money and Ahmad spent
57 of his money. In the end, Ahmad and Julie had the same amount of money left. Find the amount of money Ahmad had at first.
|
Julie |
Ahmad |
Difference |
Before |
5x1 = 5 u |
7x2 = 14 u |
9 u |
Change |
- 1x1 = - 1 u |
- 5x2 = - 10 u |
|
After |
4x1 = 4 u |
2x2 = 4 u |
|
Fraction of Julie's money left
= 1 -
15 =
45 Fraction of Ahmad's money left
= 1 -
57 =
27Ahmad and Julie had the same amount of money in the end. Make the numerators the same. LCM of 4 and 2 is 4.
45 of Julie's money =
27 of Ahmad's money
45 of Julie's money =
414 of Ahmad's money
Amount that Julie had at first = 5 u
Amount that Ahmad had at first = 14 u
Amount that Julie had less than Ahmad had at first
= 14 u - 5 u
= 9 u
9 u = 603
1 u = 603 ÷ 9 = 67
Amount that Ahmad had at first
= 14 u
= 14 x 67
= $938
Answer(s): $938