Marion had $273 less than Oscar. Marion spent ¹₇ of her money and Oscar spent ⁴₇ of his money. In the end, Oscar and Marion had the same amount of money left. Find the amount of money Oscar had at first.

	Marion	Oscar	Difference
Before	7x1 = 7 u	7x2 = 14 u	7 u
Change	- 1x1 = - 1 u	- 4x2 = - 8 u
After	6x1 = 6 u	3x2 = 6 u

Fraction of Marion's money left
= 1 - ¹₇
= ⁶₇

Fraction of Oscar's money left
= 1 - ⁴₇
= ³₇

Oscar and Marion had the same amount of money in the end. Make the numerators the same. LCM of 6 and 3 is 6.

⁶₇ of Marion's money = ³₇ of Oscar's money
⁶₇ of Marion's money = ⁶₁₄ of Oscar's money

Amount that Marion had at first = 7 u
Amount that Oscar had at first = 14 u

Amount that Marion had less than Oscar had at first
= 14 u - 7 u
= 7 u

7 u = 273

1 u = 273 ÷ 7 = 39

Amount that Oscar had at first
= 14 u
= 14 x 39
= $546

Answer(s): $546