Linda had $294 less than Liam. Linda spent
17 of her money and Liam spent
57 of his money. In the end, Liam and Linda had the same amount of money left. Find the amount of money Liam had at first.
|
Linda |
Liam |
Difference |
Before |
7x1 = 7 u |
7x3 = 21 u |
14 u |
Change |
- 1x1 = - 1 u |
- 5x3 = - 15 u |
|
After |
6x1 = 6 u |
2x3 = 6 u |
|
Fraction of Linda's money left
= 1 -
17 =
67 Fraction of Liam's money left
= 1 -
57 =
27Liam and Linda had the same amount of money in the end. Make the numerators the same. LCM of 6 and 2 is 6.
67 of Linda's money =
27 of Liam's money
67 of Linda's money =
621 of Liam's money
Amount that Linda had at first = 7 u
Amount that Liam had at first = 21 u
Amount that Linda had less than Liam had at first
= 21 u - 7 u
= 14 u
14 u = 294
1 u = 294 ÷ 14 = 21
Amount that Liam had at first
= 21 u
= 21 x 21
= $441
Answer(s): $441