Kimberly had $560 less than Sean. Kimberly spent ¹₇ of her money and Sean spent ⁵₇ of his money. In the end, Sean and Kimberly had the same amount of money left. Find the amount of money Sean had at first.

	Kimberly	Sean	Difference
Before	7x1 = 7 u	7x3 = 21 u	14 u
Change	- 1x1 = - 1 u	- 5x3 = - 15 u
After	6x1 = 6 u	2x3 = 6 u

Fraction of Kimberly's money left
= 1 - ¹₇
= ⁶₇

Fraction of Sean's money left
= 1 - ⁵₇
= ²₇

Sean and Kimberly had the same amount of money in the end. Make the numerators the same. LCM of 6 and 2 is 6.

⁶₇ of Kimberly's money = ²₇ of Sean's money
⁶₇ of Kimberly's money = ⁶₂₁ of Sean's money

Amount that Kimberly had at first = 7 u
Amount that Sean had at first = 21 u

Amount that Kimberly had less than Sean had at first
= 21 u - 7 u
= 14 u

14 u = 560

1 u = 560 ÷ 14 = 40

Amount that Sean had at first
= 21 u
= 21 x 40
= $840

Answer(s): $840