Jane had $882 less than Dylan. Jane spent
15 of her money and Dylan spent
57 of his money. In the end, Dylan and Jane had the same amount of money left. Find the amount of money Dylan had at first.
|
Jane |
Dylan |
Difference |
Before |
5x1 = 5 u |
7x2 = 14 u |
9 u |
Change |
- 1x1 = - 1 u |
- 5x2 = - 10 u |
|
After |
4x1 = 4 u |
2x2 = 4 u |
|
Fraction of Jane's money left
= 1 -
15 =
45 Fraction of Dylan's money left
= 1 -
57 =
27Dylan and Jane had the same amount of money in the end. Make the numerators the same. LCM of 4 and 2 is 4.
45 of Jane's money =
27 of Dylan's money
45 of Jane's money =
414 of Dylan's money
Amount that Jane had at first = 5 u
Amount that Dylan had at first = 14 u
Amount that Jane had less than Dylan had at first
= 14 u - 5 u
= 9 u
9 u = 882
1 u = 882 ÷ 9 = 98
Amount that Dylan had at first
= 14 u
= 14 x 98
= $1372
Answer(s): $1372