Min had $364 less than Harry. Min spent
17 of her money and Harry spent
57 of his money. In the end, Harry and Min had the same amount of money left. Find the amount of money Harry had at first.
|
Min |
Harry |
Difference |
Before |
7x1 = 7 u |
7x3 = 21 u |
14 u |
Change |
- 1x1 = - 1 u |
- 5x3 = - 15 u |
|
After |
6x1 = 6 u |
2x3 = 6 u |
|
Fraction of Min's money left
= 1 -
17 =
67 Fraction of Harry's money left
= 1 -
57 =
27Harry and Min had the same amount of money in the end. Make the numerators the same. LCM of 6 and 2 is 6.
67 of Min's money =
27 of Harry's money
67 of Min's money =
621 of Harry's money
Amount that Min had at first = 7 u
Amount that Harry had at first = 21 u
Amount that Min had less than Harry had at first
= 21 u - 7 u
= 14 u
14 u = 364
1 u = 364 ÷ 14 = 26
Amount that Harry had at first
= 21 u
= 21 x 26
= $546
Answer(s): $546