Jane had $468 less than Daniel. Jane spent
14 of her money and Daniel spent
57 of his money. In the end, Daniel and Jane had the same amount of money left. Find the amount of money Daniel had at first.
|
Jane |
Daniel |
Difference |
Before |
4x2 = 8 u |
7x3 = 21 u |
13 u |
Change |
- 1x2 = - 2 u |
- 5x3 = - 15 u |
|
After |
3x2 = 6 u |
2x3 = 6 u |
|
Fraction of Jane's money left
= 1 -
14 =
34 Fraction of Daniel's money left
= 1 -
57 =
27Daniel and Jane had the same amount of money in the end. Make the numerators the same. LCM of 3 and 2 is 6.
34 of Jane's money =
27 of Daniel's money
68 of Jane's money =
621 of Daniel's money
Amount that Jane had at first = 8 u
Amount that Daniel had at first = 21 u
Amount that Jane had less than Daniel had at first
= 21 u - 8 u
= 13 u
13 u = 468
1 u = 468 ÷ 13 = 36
Amount that Daniel had at first
= 21 u
= 21 x 36
= $756
Answer(s): $756