Eva had $1092 less than Luis. Eva spent
17 of her money and Luis spent
57 of his money. In the end, Luis and Eva had the same amount of money left. Find the amount of money Luis had at first.
|
Eva |
Luis |
Difference |
Before |
7x1 = 7 u |
7x3 = 21 u |
14 u |
Change |
- 1x1 = - 1 u |
- 5x3 = - 15 u |
|
After |
6x1 = 6 u |
2x3 = 6 u |
|
Fraction of Eva's money left
= 1 -
17 =
67 Fraction of Luis's money left
= 1 -
57 =
27Luis and Eva had the same amount of money in the end. Make the numerators the same. LCM of 6 and 2 is 6.
67 of Eva's money =
27 of Luis's money
67 of Eva's money =
621 of Luis's money
Amount that Eva had at first = 7 u
Amount that Luis had at first = 21 u
Amount that Eva had less than Luis had at first
= 21 u - 7 u
= 14 u
14 u = 1092
1 u = 1092 ÷ 14 = 78
Amount that Luis had at first
= 21 u
= 21 x 78
= $1638
Answer(s): $1638