Pamela had $1079 less than Albert. Pamela spent ¹₄ of her money and Albert spent ⁵₇ of his money. In the end, Albert and Pamela had the same amount of money left. Find the amount of money Albert had at first.

	Pamela	Albert	Difference
Before	4x2 = 8 u	7x3 = 21 u	13 u
Change	- 1x2 = - 2 u	- 5x3 = - 15 u
After	3x2 = 6 u	2x3 = 6 u

Fraction of Pamela's money left
= 1 - ¹₄
= ³₄

Fraction of Albert's money left
= 1 - ⁵₇
= ²₇

Albert and Pamela had the same amount of money in the end. Make the numerators the same. LCM of 3 and 2 is 6.

³₄ of Pamela's money = ²₇ of Albert's money
⁶₈ of Pamela's money = ⁶₂₁ of Albert's money

Amount that Pamela had at first = 8 u
Amount that Albert had at first = 21 u

Amount that Pamela had less than Albert had at first
= 21 u - 8 u
= 13 u

13 u = 1079

1 u = 1079 ÷ 13 = 83

Amount that Albert had at first
= 21 u
= 21 x 83
= $1743

Answer(s): $1743