Irene had $339 less than Ivan. Irene spent
13 of her money and Ivan spent
23 of his money. In the end, Ivan and Irene had the same amount of money left. Find the amount of money Ivan had at first.
|
Irene |
Ivan |
Difference |
Before |
3x1 = 3 u |
3x2 = 6 u |
3 u |
Change |
- 1x1 = - 1 u |
- 2x2 = - 4 u |
|
After |
2x1 = 2 u |
1x2 = 2 u |
|
Fraction of Irene's money left
= 1 -
13 =
23 Fraction of Ivan's money left
= 1 -
23 =
13Ivan and Irene had the same amount of money in the end. Make the numerators the same. LCM of 2 and 1 is 2.
23 of Irene's money =
13 of Ivan's money
23 of Irene's money =
26 of Ivan's money
Amount that Irene had at first = 3 u
Amount that Ivan had at first = 6 u
Amount that Irene had less than Ivan had at first
= 6 u - 3 u
= 3 u
3 u = 339
1 u = 339 ÷ 3 = 113
Amount that Ivan had at first
= 6 u
= 6 x 113
= $678
Answer(s): $678