Shannon had $217 less than Simon. Shannon spent ¹₇ of her money and Simon spent ⁴₇ of his money. In the end, Simon and Shannon had the same amount of money left. Find the amount of money Simon had at first.

	Shannon	Simon	Difference
Before	7x1 = 7 u	7x2 = 14 u	7 u
Change	- 1x1 = - 1 u	- 4x2 = - 8 u
After	6x1 = 6 u	3x2 = 6 u

Fraction of Shannon's money left
= 1 - ¹₇
= ⁶₇

Fraction of Simon's money left
= 1 - ⁴₇
= ³₇

Simon and Shannon had the same amount of money in the end. Make the numerators the same. LCM of 6 and 3 is 6.

⁶₇ of Shannon's money = ³₇ of Simon's money
⁶₇ of Shannon's money = ⁶₁₄ of Simon's money

Amount that Shannon had at first = 7 u
Amount that Simon had at first = 14 u

Amount that Shannon had less than Simon had at first
= 14 u - 7 u
= 7 u

7 u = 217

1 u = 217 ÷ 7 = 31

Amount that Simon had at first
= 14 u
= 14 x 31
= $434

Answer(s): $434