Kimberly had $342 less than Oscar. Kimberly spent
15 of her money and Oscar spent
57 of his money. In the end, Oscar and Kimberly had the same amount of money left. Find the amount of money Oscar had at first.
|
Kimberly |
Oscar |
Difference |
Before |
5x1 = 5 u |
7x2 = 14 u |
9 u |
Change |
- 1x1 = - 1 u |
- 5x2 = - 10 u |
|
After |
4x1 = 4 u |
2x2 = 4 u |
|
Fraction of Kimberly's money left
= 1 -
15 =
45 Fraction of Oscar's money left
= 1 -
57 =
27Oscar and Kimberly had the same amount of money in the end. Make the numerators the same. LCM of 4 and 2 is 4.
45 of Kimberly's money =
27 of Oscar's money
45 of Kimberly's money =
414 of Oscar's money
Amount that Kimberly had at first = 5 u
Amount that Oscar had at first = 14 u
Amount that Kimberly had less than Oscar had at first
= 14 u - 5 u
= 9 u
9 u = 342
1 u = 342 ÷ 9 = 38
Amount that Oscar had at first
= 14 u
= 14 x 38
= $532
Answer(s): $532