Kimberly had $420 less than Warren. Kimberly spent
14 of her money and Warren spent
35 of his money. In the end, Warren and Kimberly had the same amount of money left. Find the amount of money Warren had at first.
|
Kimberly |
Warren |
Difference |
Before |
4x2 = 8 u |
5x3 = 15 u |
7 u |
Change |
- 1x2 = - 2 u |
- 3x3 = - 9 u |
|
After |
3x2 = 6 u |
2x3 = 6 u |
|
Fraction of Kimberly's money left
= 1 -
14 =
34 Fraction of Warren's money left
= 1 -
35 =
25Warren and Kimberly had the same amount of money in the end. Make the numerators the same. LCM of 3 and 2 is 6.
34 of Kimberly's money =
25 of Warren's money
68 of Kimberly's money =
615 of Warren's money
Amount that Kimberly had at first = 8 u
Amount that Warren had at first = 15 u
Amount that Kimberly had less than Warren had at first
= 15 u - 8 u
= 7 u
7 u = 420
1 u = 420 ÷ 7 = 60
Amount that Warren had at first
= 15 u
= 15 x 60
= $900
Answer(s): $900