Sarah had $256 less than Howard. Sarah spent
17 of her money and Howard spent
35 of his money. In the end, Howard and Sarah had the same amount of money left. Find the amount of money Howard had at first.
|
Sarah |
Howard |
Difference |
Before |
7x1 = 7 u |
5x3 = 15 u |
8 u |
Change |
- 1x1 = - 1 u |
- 3x3 = - 9 u |
|
After |
6x1 = 6 u |
2x3 = 6 u |
|
Fraction of Sarah's money left
= 1 -
17 =
67 Fraction of Howard's money left
= 1 -
35 =
25Howard and Sarah had the same amount of money in the end. Make the numerators the same. LCM of 6 and 2 is 6.
67 of Sarah's money =
25 of Howard's money
67 of Sarah's money =
615 of Howard's money
Amount that Sarah had at first = 7 u
Amount that Howard had at first = 15 u
Amount that Sarah had less than Howard had at first
= 15 u - 7 u
= 8 u
8 u = 256
1 u = 256 ÷ 8 = 32
Amount that Howard had at first
= 15 u
= 15 x 32
= $480
Answer(s): $480