Abi had $198 less than Fred. Abi spent
15 of her money and Fred spent
57 of his money. In the end, Fred and Abi had the same amount of money left. Find the amount of money Fred had at first.
|
Abi |
Fred |
Difference |
Before |
5x1 = 5 u |
7x2 = 14 u |
9 u |
Change |
- 1x1 = - 1 u |
- 5x2 = - 10 u |
|
After |
4x1 = 4 u |
2x2 = 4 u |
|
Fraction of Abi's money left
= 1 -
15 =
45 Fraction of Fred's money left
= 1 -
57 =
27Fred and Abi had the same amount of money in the end. Make the numerators the same. LCM of 4 and 2 is 4.
45 of Abi's money =
27 of Fred's money
45 of Abi's money =
414 of Fred's money
Amount that Abi had at first = 5 u
Amount that Fred had at first = 14 u
Amount that Abi had less than Fred had at first
= 14 u - 5 u
= 9 u
9 u = 198
1 u = 198 ÷ 9 = 22
Amount that Fred had at first
= 14 u
= 14 x 22
= $308
Answer(s): $308