Mary had $327 less than Peter. Mary spent
13 of her money and Peter spent
23 of his money. In the end, Peter and Mary had the same amount of money left. Find the amount of money Peter had at first.
|
Mary |
Peter |
Difference |
Before |
3x1 = 3 u |
3x2 = 6 u |
3 u |
Change |
- 1x1 = - 1 u |
- 2x2 = - 4 u |
|
After |
2x1 = 2 u |
1x2 = 2 u |
|
Fraction of Mary's money left
= 1 -
13 =
23 Fraction of Peter's money left
= 1 -
23 =
13Peter and Mary had the same amount of money in the end. Make the numerators the same. LCM of 2 and 1 is 2.
23 of Mary's money =
13 of Peter's money
23 of Mary's money =
26 of Peter's money
Amount that Mary had at first = 3 u
Amount that Peter had at first = 6 u
Amount that Mary had less than Peter had at first
= 6 u - 3 u
= 3 u
3 u = 327
1 u = 327 ÷ 3 = 109
Amount that Peter had at first
= 6 u
= 6 x 109
= $654
Answer(s): $654