Yoko had $742 less than Ken. Yoko spent
14 of her money and Ken spent
35 of his money. In the end, Ken and Yoko had the same amount of money left. Find the amount of money Ken had at first.
|
Yoko |
Ken |
Difference |
Before |
4x2 = 8 u |
5x3 = 15 u |
7 u |
Change |
- 1x2 = - 2 u |
- 3x3 = - 9 u |
|
After |
3x2 = 6 u |
2x3 = 6 u |
|
Fraction of Yoko's money left
= 1 -
14 =
34 Fraction of Ken's money left
= 1 -
35 =
25Ken and Yoko had the same amount of money in the end. Make the numerators the same. LCM of 3 and 2 is 6.
34 of Yoko's money =
25 of Ken's money
68 of Yoko's money =
615 of Ken's money
Amount that Yoko had at first = 8 u
Amount that Ken had at first = 15 u
Amount that Yoko had less than Ken had at first
= 15 u - 8 u
= 7 u
7 u = 742
1 u = 742 ÷ 7 = 106
Amount that Ken had at first
= 15 u
= 15 x 106
= $1590
Answer(s): $1590