Diana had $651 less than Luke. Diana spent
17 of her money and Luke spent
47 of his money. In the end, Luke and Diana had the same amount of money left. Find the amount of money Luke had at first.
|
Diana |
Luke |
Difference |
Before |
7x1 = 7 u |
7x2 = 14 u |
7 u |
Change |
- 1x1 = - 1 u |
- 4x2 = - 8 u |
|
After |
6x1 = 6 u |
3x2 = 6 u |
|
Fraction of Diana's money left
= 1 -
17 =
67 Fraction of Luke's money left
= 1 -
47 =
37Luke and Diana had the same amount of money in the end. Make the numerators the same. LCM of 6 and 3 is 6.
67 of Diana's money =
37 of Luke's money
67 of Diana's money =
614 of Luke's money
Amount that Diana had at first = 7 u
Amount that Luke had at first = 14 u
Amount that Diana had less than Luke had at first
= 14 u - 7 u
= 7 u
7 u = 651
1 u = 651 ÷ 7 = 93
Amount that Luke had at first
= 14 u
= 14 x 93
= $1302
Answer(s): $1302