Risa had $375 less than Riordan. Risa spent
13 of her money and Riordan spent
47 of his money. In the end, Riordan and Risa had the same amount of money left. Find the amount of money Riordan had at first.
|
Risa |
Riordan |
Difference |
Before |
3x3 = 9 u |
7x2 = 14 u |
5 u |
Change |
- 1x3 = - 3 u |
- 4x2 = - 8 u |
|
After |
2x3 = 6 u |
3x2 = 6 u |
|
Fraction of Risa's money left
= 1 -
13 =
23 Fraction of Riordan's money left
= 1 -
47 =
37Riordan and Risa had the same amount of money in the end. Make the numerators the same. LCM of 2 and 3 is 6.
23 of Risa's money =
37 of Riordan's money
69 of Risa's money =
614 of Riordan's money
Amount that Risa had at first = 9 u
Amount that Riordan had at first = 14 u
Amount that Risa had less than Riordan had at first
= 14 u - 9 u
= 5 u
5 u = 375
1 u = 375 ÷ 5 = 75
Amount that Riordan had at first
= 14 u
= 14 x 75
= $1050
Answer(s): $1050