Opal had $1853 less than Ken. Opal spent
16 of her money and Ken spent
47 of his money. In the end, Ken and Opal had the same amount of money left. Find the amount of money Ken had at first.
|
Opal |
Ken |
Difference |
Before |
6x3 = 18 u |
7x5 = 35 u |
17 u |
Change |
- 1x3 = - 3 u |
- 4x5 = - 20 u |
|
After |
5x3 = 15 u |
3x5 = 15 u |
|
Fraction of Opal's money left
= 1 -
16 =
56 Fraction of Ken's money left
= 1 -
47 =
37Ken and Opal had the same amount of money in the end. Make the numerators the same. LCM of 5 and 3 is 15.
56 of Opal's money =
37 of Ken's money
1518 of Opal's money =
1535 of Ken's money
Amount that Opal had at first = 18 u
Amount that Ken had at first = 35 u
Amount that Opal had less than Ken had at first
= 35 u - 18 u
= 17 u
17 u = 1853
1 u = 1853 ÷ 17 = 109
Amount that Ken had at first
= 35 u
= 35 x 109
= $3815
Answer(s): $3815