Kimberly had $1863 less than Justin. Kimberly spent ¹₆ of her money and Justin spent ⁵₇ of his money. In the end, Justin and Kimberly had the same amount of money left. Find the amount of money Justin had at first.

	Kimberly	Justin	Difference
Before	6x2 = 12 u	7x5 = 35 u	23 u
Change	- 1x2 = - 2 u	- 5x5 = - 25 u
After	5x2 = 10 u	2x5 = 10 u

Fraction of Kimberly's money left
= 1 - ¹₆
= ⁵₆

Fraction of Justin's money left
= 1 - ⁵₇
= ²₇

Justin and Kimberly had the same amount of money in the end. Make the numerators the same. LCM of 5 and 2 is 10.

⁵₆ of Kimberly's money = ²₇ of Justin's money
¹⁰₁₂ of Kimberly's money = ¹⁰₃₅ of Justin's money

Amount that Kimberly had at first = 12 u
Amount that Justin had at first = 35 u

Amount that Kimberly had less than Justin had at first
= 35 u - 12 u
= 23 u

23 u = 1863

1 u = 1863 ÷ 23 = 81

Amount that Justin had at first
= 35 u
= 35 x 81
= $2835

Answer(s): $2835