Yoko had $494 less than Tim. Yoko spent
14 of her money and Tim spent
57 of his money. In the end, Tim and Yoko had the same amount of money left. Find the amount of money Tim had at first.
|
Yoko |
Tim |
Difference |
Before |
4x2 = 8 u |
7x3 = 21 u |
13 u |
Change |
- 1x2 = - 2 u |
- 5x3 = - 15 u |
|
After |
3x2 = 6 u |
2x3 = 6 u |
|
Fraction of Yoko's money left
= 1 -
14 =
34 Fraction of Tim's money left
= 1 -
57 =
27Tim and Yoko had the same amount of money in the end. Make the numerators the same. LCM of 3 and 2 is 6.
34 of Yoko's money =
27 of Tim's money
68 of Yoko's money =
621 of Tim's money
Amount that Yoko had at first = 8 u
Amount that Tim had at first = 21 u
Amount that Yoko had less than Tim had at first
= 21 u - 8 u
= 13 u
13 u = 494
1 u = 494 ÷ 13 = 38
Amount that Tim had at first
= 21 u
= 21 x 38
= $798
Answer(s): $798