Jade had $968 less than David. Jade spent
17 of her money and David spent
23 of his money. In the end, David and Jade had the same amount of money left. Find the amount of money David had at first.
|
Jade |
David |
Difference |
Before |
7x1 = 7 u |
3x6 = 18 u |
11 u |
Change |
- 1x1 = - 1 u |
- 2x6 = - 12 u |
|
After |
6x1 = 6 u |
1x6 = 6 u |
|
Fraction of Jade's money left
= 1 -
17 =
67 Fraction of David's money left
= 1 -
23 =
13David and Jade had the same amount of money in the end. Make the numerators the same. LCM of 6 and 1 is 6.
67 of Jade's money =
13 of David's money
67 of Jade's money =
618 of David's money
Amount that Jade had at first = 7 u
Amount that David had at first = 18 u
Amount that Jade had less than David had at first
= 18 u - 7 u
= 11 u
11 u = 968
1 u = 968 ÷ 11 = 88
Amount that David had at first
= 18 u
= 18 x 88
= $1584
Answer(s): $1584