Jade had $637 less than Brandon. Jade spent
15 of her money and Brandon spent
47 of his money. In the end, Brandon and Jade had the same amount of money left. Find the amount of money Brandon had at first.
|
Jade |
Brandon |
Difference |
Before |
5x3 = 15 u |
7x4 = 28 u |
13 u |
Change |
- 1x3 = - 3 u |
- 4x4 = - 16 u |
|
After |
4x3 = 12 u |
3x4 = 12 u |
|
Fraction of Jade's money left
= 1 -
15 =
45 Fraction of Brandon's money left
= 1 -
47 =
37Brandon and Jade had the same amount of money in the end. Make the numerators the same. LCM of 4 and 3 is 12.
45 of Jade's money =
37 of Brandon's money
1215 of Jade's money =
1228 of Brandon's money
Amount that Jade had at first = 15 u
Amount that Brandon had at first = 28 u
Amount that Jade had less than Brandon had at first
= 28 u - 15 u
= 13 u
13 u = 637
1 u = 637 ÷ 13 = 49
Amount that Brandon had at first
= 28 u
= 28 x 49
= $1372
Answer(s): $1372