Roshel had $525 less than Cody. Roshel spent
14 of her money and Cody spent
23 of his money. In the end, Cody and Roshel had the same amount of money left. Find the amount of money Cody had at first.
|
Roshel |
Cody |
Difference |
Before |
4x1 = 4 u |
3x3 = 9 u |
5 u |
Change |
- 1x1 = - 1 u |
- 2x3 = - 6 u |
|
After |
3x1 = 3 u |
1x3 = 3 u |
|
Fraction of Roshel's money left
= 1 -
14 =
34 Fraction of Cody's money left
= 1 -
23 =
13Cody and Roshel had the same amount of money in the end. Make the numerators the same. LCM of 3 and 1 is 3.
34 of Roshel's money =
13 of Cody's money
34 of Roshel's money =
39 of Cody's money
Amount that Roshel had at first = 4 u
Amount that Cody had at first = 9 u
Amount that Roshel had less than Cody had at first
= 9 u - 4 u
= 5 u
5 u = 525
1 u = 525 ÷ 5 = 105
Amount that Cody had at first
= 9 u
= 9 x 105
= $945
Answer(s): $945