Jen had $833 less than Ahmad. Jen spent
17 of her money and Ahmad spent
47 of his money. In the end, Ahmad and Jen had the same amount of money left. Find the amount of money Ahmad had at first.
|
Jen |
Ahmad |
Difference |
Before |
7x1 = 7 u |
7x2 = 14 u |
7 u |
Change |
- 1x1 = - 1 u |
- 4x2 = - 8 u |
|
After |
6x1 = 6 u |
3x2 = 6 u |
|
Fraction of Jen's money left
= 1 -
17 =
67 Fraction of Ahmad's money left
= 1 -
47 =
37Ahmad and Jen had the same amount of money in the end. Make the numerators the same. LCM of 6 and 3 is 6.
67 of Jen's money =
37 of Ahmad's money
67 of Jen's money =
614 of Ahmad's money
Amount that Jen had at first = 7 u
Amount that Ahmad had at first = 14 u
Amount that Jen had less than Ahmad had at first
= 14 u - 7 u
= 7 u
7 u = 833
1 u = 833 ÷ 7 = 119
Amount that Ahmad had at first
= 14 u
= 14 x 119
= $1666
Answer(s): $1666