Tiffany had $1442 less than Julian. Tiffany spent
17 of her money and Julian spent
57 of his money. In the end, Julian and Tiffany had the same amount of money left. Find the amount of money Julian had at first.
|
Tiffany |
Julian |
Difference |
Before |
7x1 = 7 u |
7x3 = 21 u |
14 u |
Change |
- 1x1 = - 1 u |
- 5x3 = - 15 u |
|
After |
6x1 = 6 u |
2x3 = 6 u |
|
Fraction of Tiffany's money left
= 1 -
17 =
67 Fraction of Julian's money left
= 1 -
57 =
27Julian and Tiffany had the same amount of money in the end. Make the numerators the same. LCM of 6 and 2 is 6.
67 of Tiffany's money =
27 of Julian's money
67 of Tiffany's money =
621 of Julian's money
Amount that Tiffany had at first = 7 u
Amount that Julian had at first = 21 u
Amount that Tiffany had less than Julian had at first
= 21 u - 7 u
= 14 u
14 u = 1442
1 u = 1442 ÷ 14 = 103
Amount that Julian had at first
= 21 u
= 21 x 103
= $2163
Answer(s): $2163