Nicole had $806 less than Howard. Nicole spent
14 of her money and Howard spent
57 of his money. In the end, Howard and Nicole had the same amount of money left. Find the amount of money Howard had at first.
|
Nicole |
Howard |
Difference |
Before |
4x2 = 8 u |
7x3 = 21 u |
13 u |
Change |
- 1x2 = - 2 u |
- 5x3 = - 15 u |
|
After |
3x2 = 6 u |
2x3 = 6 u |
|
Fraction of Nicole's money left
= 1 -
14 =
34 Fraction of Howard's money left
= 1 -
57 =
27Howard and Nicole had the same amount of money in the end. Make the numerators the same. LCM of 3 and 2 is 6.
34 of Nicole's money =
27 of Howard's money
68 of Nicole's money =
621 of Howard's money
Amount that Nicole had at first = 8 u
Amount that Howard had at first = 21 u
Amount that Nicole had less than Howard had at first
= 21 u - 8 u
= 13 u
13 u = 806
1 u = 806 ÷ 13 = 62
Amount that Howard had at first
= 21 u
= 21 x 62
= $1302
Answer(s): $1302