Xylia had $455 less than Michael. Michael spent 0.6 of his money and Xylia spent 0.4 of her money. In the end, Michael and Xylia had the same amount of money left. Find the amount of money Xylia had at first.
|
Xylia |
Michael |
Difference |
Before |
10 u |
15 u |
5 u |
Change |
- 2 u |
- 3 u |
|
After |
6 u |
6 u |
|
0.6 =
35 Fraction of Michael's amount left
= 1 -
35 =
25 0.4 =
25 Fraction of Xylia's amount left
= 1 -
25 =
35 The amount that Michael and Xylia each had in the end is the same. Make the numerators the same. LCM of 2 and 3 is 6.
25 of Michael's amount =
35 of Xylia's amount
615 of Michael's amount =
610 of Xylia's amount
Amount that Xylia had less than Michael
= 15 u - 10 u
= 5 u
5 u = 455
1 u = 455 ÷ 5 = 91
Amount that Xylia had at first
= 10 u
= 10 x 91
= $910
Answer(s): $910