Betty had $375 less than Dylan. Dylan spent 0.8 of his money and Betty spent 0.3 of her money. In the end, Dylan and Betty had the same amount of money left. Find the amount of money Betty had at first.
| |
Betty |
Dylan |
Difference |
| Before |
10 u |
35 u |
25 u |
| Change |
- 1 u |
- 7 u |
|
| After |
7 u |
7 u |
|
0.8 =
45 Fraction of Dylan's amount left
= 1 -
45 =
15 0.3 =
310 Fraction of Betty's amount left
= 1 -
310 =
710 The amount that Dylan and Betty each had in the end is the same. Make the numerators the same. LCM of 1 and 7 is 7.
15 of Dylan's amount =
710 of Betty's amount
735 of Dylan's amount =
710 of Betty's amount
Amount that Betty had less than Dylan
= 35 u - 10 u
= 25 u
25 u = 375
1 u = 375 ÷ 25 = 15
Amount that Betty had at first
= 10 u
= 10 x 15
= $150
Answer(s): $150
