Marion had $450 less than Bobby. Bobby spent 0.8 of his money and Marion spent 0.3 of her money. In the end, Bobby and Marion had the same amount of money left. Find the amount of money Marion had at first.
|
Marion |
Bobby |
Difference |
Before |
10 u |
35 u |
25 u |
Change |
- 1 u |
- 7 u |
|
After |
7 u |
7 u |
|
0.8 =
45 Fraction of Bobby's amount left
= 1 -
45 =
15 0.3 =
310 Fraction of Marion's amount left
= 1 -
310 =
710 The amount that Bobby and Marion each had in the end is the same. Make the numerators the same. LCM of 1 and 7 is 7.
15 of Bobby's amount =
710 of Marion's amount
735 of Bobby's amount =
710 of Marion's amount
Amount that Marion had less than Bobby
= 35 u - 10 u
= 25 u
25 u = 450
1 u = 450 ÷ 25 = 18
Amount that Marion had at first
= 10 u
= 10 x 18
= $180
Answer(s): $180