Min had $480 less than Henry. Henry spent 0.7 of his money and Min spent 0.3 of her money. In the end, Henry and Min had the same amount of money left. Find the amount of money Min had at first.
| |
Min |
Henry |
Difference |
| Before |
30 u |
70 u |
40 u |
| Change |
- 3 u |
- 7 u |
|
| After |
21 u |
21 u |
|
0.7 =
710 Fraction of Henry's amount left
= 1 -
710 =
310 0.3 =
310 Fraction of Min's amount left
= 1 -
310 =
710 The amount that Henry and Min each had in the end is the same. Make the numerators the same. LCM of 3 and 7 is 21.
310 of Henry's amount =
710 of Min's amount
2170 of Henry's amount =
2130 of Min's amount
Amount that Min had less than Henry
= 70 u - 30 u
= 40 u
40 u = 480
1 u = 480 ÷ 40 = 12
Amount that Min had at first
= 30 u
= 30 x 12
= $360
Answer(s): $360
