Marion had $400 less than Cole. Cole spent 0.7 of his money and Marion spent 0.3 of her money. In the end, Cole and Marion had the same amount of money left. Find the amount of money Marion had at first.
| |
Marion |
Cole |
Difference |
| Before |
30 u |
70 u |
40 u |
| Change |
- 3 u |
- 7 u |
|
| After |
21 u |
21 u |
|
0.7 =
710 Fraction of Cole's amount left
= 1 -
710 =
310 0.3 =
310 Fraction of Marion's amount left
= 1 -
310 =
710 The amount that Cole and Marion each had in the end is the same. Make the numerators the same. LCM of 3 and 7 is 21.
310 of Cole's amount =
710 of Marion's amount
2170 of Cole's amount =
2130 of Marion's amount
Amount that Marion had less than Cole
= 70 u - 30 u
= 40 u
40 u = 400
1 u = 400 ÷ 40 = 10
Amount that Marion had at first
= 30 u
= 30 x 10
= $300
Answer(s): $300
