Marion had $500 less than Ahmad. Ahmad spent 0.6 of his money and Marion spent 0.4 of her money. In the end, Ahmad and Marion had the same amount of money left. Find the amount of money Marion had at first.
|
Marion |
Ahmad |
Difference |
Before |
10 u |
15 u |
5 u |
Change |
- 2 u |
- 3 u |
|
After |
6 u |
6 u |
|
0.6 =
35 Fraction of Ahmad's amount left
= 1 -
35 =
25 0.4 =
25 Fraction of Marion's amount left
= 1 -
25 =
35 The amount that Ahmad and Marion each had in the end is the same. Make the numerators the same. LCM of 2 and 3 is 6.
25 of Ahmad's amount =
35 of Marion's amount
615 of Ahmad's amount =
610 of Marion's amount
Amount that Marion had less than Ahmad
= 15 u - 10 u
= 5 u
5 u = 500
1 u = 500 ÷ 5 = 100
Amount that Marion had at first
= 10 u
= 10 x 100
= $1000
Answer(s): $1000