Kimberly had $420 less than Gabriel. Gabriel spent 0.9 of his money and Kimberly spent 0.3 of her money. In the end, Gabriel and Kimberly had the same amount of money left. Find the amount of money Kimberly had at first.
|
Kimberly |
Gabriel |
Difference |
Before |
10 u |
70 u |
60 u |
Change |
- 1 u |
- 7 u |
|
After |
7 u |
7 u |
|
0.9 =
910 Fraction of Gabriel's amount left
= 1 -
910 =
110 0.3 =
310 Fraction of Kimberly's amount left
= 1 -
310 =
710 The amount that Gabriel and Kimberly each had in the end is the same. Make the numerators the same. LCM of 1 and 7 is 7.
110 of Gabriel's amount =
710 of Kimberly's amount
770 of Gabriel's amount =
710 of Kimberly's amount
Amount that Kimberly had less than Gabriel
= 70 u - 10 u
= 60 u
60 u = 420
1 u = 420 ÷ 60 = 7
Amount that Kimberly had at first
= 10 u
= 10 x 7
= $70
Answer(s): $70