Elyse had $480 less than Gabriel. Gabriel spent 0.7 of his money and Elyse spent 0.3 of her money. In the end, Gabriel and Elyse had the same amount of money left. Find the amount of money Elyse had at first.
|
Elyse |
Gabriel |
Difference |
Before |
30 u |
70 u |
40 u |
Change |
- 3 u |
- 7 u |
|
After |
21 u |
21 u |
|
0.7 =
710 Fraction of Gabriel's amount left
= 1 -
710 =
310 0.3 =
310 Fraction of Elyse's amount left
= 1 -
310 =
710 The amount that Gabriel and Elyse each had in the end is the same. Make the numerators the same. LCM of 3 and 7 is 21.
310 of Gabriel's amount =
710 of Elyse's amount
2170 of Gabriel's amount =
2130 of Elyse's amount
Amount that Elyse had less than Gabriel
= 70 u - 30 u
= 40 u
40 u = 480
1 u = 480 ÷ 40 = 12
Amount that Elyse had at first
= 30 u
= 30 x 12
= $360
Answer(s): $360