Jaslyn had $460 less than Dylan. Dylan spent 0.8 of his money and Jaslyn spent 0.4 of her money. In the end, Dylan and Jaslyn had the same amount of money left. Find the amount of money Jaslyn had at first.
| |
Jaslyn |
Dylan |
Difference |
| Before |
5 u |
15 u |
10 u |
| Change |
- 1 u |
- 3 u |
|
| After |
3 u |
3 u |
|
0.8 =
45 Fraction of Dylan's amount left
= 1 -
45 =
15 0.4 =
25 Fraction of Jaslyn's amount left
= 1 -
25 =
35 The amount that Dylan and Jaslyn each had in the end is the same. Make the numerators the same. LCM of 1 and 3 is 3.
15 of Dylan's amount =
35 of Jaslyn's amount
315 of Dylan's amount =
35 of Jaslyn's amount
Amount that Jaslyn had less than Dylan
= 15 u - 5 u
= 10 u
10 u = 460
1 u = 460 ÷ 10 = 46
Amount that Jaslyn had at first
= 5 u
= 5 x 46
= $230
Answer(s): $230
