Julie had $440 less than Albert. Albert spent 0.7 of his money and Julie spent 0.3 of her money. In the end, Albert and Julie had the same amount of money left. Find the amount of money Julie had at first.
| |
Julie |
Albert |
Difference |
| Before |
30 u |
70 u |
40 u |
| Change |
- 3 u |
- 7 u |
|
| After |
21 u |
21 u |
|
0.7 =
710 Fraction of Albert's amount left
= 1 -
710 =
310 0.3 =
310 Fraction of Julie's amount left
= 1 -
310 =
710 The amount that Albert and Julie each had in the end is the same. Make the numerators the same. LCM of 3 and 7 is 21.
310 of Albert's amount =
710 of Julie's amount
2170 of Albert's amount =
2130 of Julie's amount
Amount that Julie had less than Albert
= 70 u - 30 u
= 40 u
40 u = 440
1 u = 440 ÷ 40 = 11
Amount that Julie had at first
= 30 u
= 30 x 11
= $330
Answer(s): $330
