Jaslyn had $445 less than Simon. Simon spent 0.6 of his money and Jaslyn spent 0.4 of her money. In the end, Simon and Jaslyn had the same amount of money left. Find the amount of money Jaslyn had at first.
| |
Jaslyn |
Simon |
Difference |
| Before |
10 u |
15 u |
5 u |
| Change |
- 2 u |
- 3 u |
|
| After |
6 u |
6 u |
|
0.6 =
35 Fraction of Simon's amount left
= 1 -
35 =
25 0.4 =
25 Fraction of Jaslyn's amount left
= 1 -
25 =
35 The amount that Simon and Jaslyn each had in the end is the same. Make the numerators the same. LCM of 2 and 3 is 6.
25 of Simon's amount =
35 of Jaslyn's amount
615 of Simon's amount =
610 of Jaslyn's amount
Amount that Jaslyn had less than Simon
= 15 u - 10 u
= 5 u
5 u = 445
1 u = 445 ÷ 5 = 89
Amount that Jaslyn had at first
= 10 u
= 10 x 89
= $890
Answer(s): $890
