Tina had $420 less than Jenson. Jenson spent 0.9 of his money and Tina spent 0.2 of her money. In the end, Jenson and Tina had the same amount of money left. Find the amount of money Tina had at first.
| |
Tina |
Jenson |
Difference |
| Before |
5 u |
40 u |
35 u |
| Change |
- 1 u |
- 4 u |
|
| After |
4 u |
4 u |
|
0.9 =
910 Fraction of Jenson's amount left
= 1 -
910 =
110 0.2 =
15 Fraction of Tina's amount left
= 1 -
15 =
45 The amount that Jenson and Tina each had in the end is the same. Make the numerators the same. LCM of 1 and 4 is 4.
110 of Jenson's amount =
45 of Tina's amount
440 of Jenson's amount =
45 of Tina's amount
Amount that Tina had less than Jenson
= 40 u - 5 u
= 35 u
35 u = 420
1 u = 420 ÷ 35 = 12
Amount that Tina had at first
= 5 u
= 5 x 12
= $60
Answer(s): $60
