Min had $425 less than George. George spent 0.6 of his money and Min spent 0.4 of her money. In the end, George and Min had the same amount of money left. Find the amount of money Min had at first.
| |
Min |
George |
Difference |
| Before |
10 u |
15 u |
5 u |
| Change |
- 2 u |
- 3 u |
|
| After |
6 u |
6 u |
|
0.6 =
35 Fraction of George's amount left
= 1 -
35 =
25 0.4 =
25 Fraction of Min's amount left
= 1 -
25 =
35 The amount that George and Min each had in the end is the same. Make the numerators the same. LCM of 2 and 3 is 6.
25 of George's amount =
35 of Min's amount
615 of George's amount =
610 of Min's amount
Amount that Min had less than George
= 15 u - 10 u
= 5 u
5 u = 425
1 u = 425 ÷ 5 = 85
Amount that Min had at first
= 10 u
= 10 x 85
= $850
Answer(s): $850
