50% of Cathy's amount was $320 less than Peter's amount. When Cathy spent 40% of her amount and Peter spent 60% of his amount, they had the same amount of amount left. Find the amount that Peter had at first.
|
Cathy |
Peter |
Before |
10 u |
15 u |
Change |
- 4 u |
- 9 u |
After |
6 u |
6 u |
Percentage of Cathy's amount left
= 100% - 40%
= 60%
Percentage of Peter's amount left
= 100% - 60%
= 40%
60% =
60100 =
35 40% =
40100 =
25 The amounts of amount that Cathy and Peter had left were the same. Make the numerators the same.
35 of Cathy's amount =
25 of Peter's amount
610 of Cathy's amount =
615 of Peter's amount
Amount that Cathy had = 10 u
50% of the amount that Cathy had
= 50% x 10 u
=
50100 x 10 u
= 5 u
Difference between Peter's amount and 50% of Cathy's amount
= 15 u - 5 u
= 10 u
10 u = 320
1 u = 320 ÷ 10 = 32
Amount that Peter had at first
= 15 u
= 15 x 32
= $480
Answer(s): $480