90% of Linda's amount was $468 more than Seth's amount. When Linda spent 55% of her amount and Seth spent 30% of his amount, they had the same amount of amount left. Find the amount that Seth had at first.
|
90% of Linda's amount |
Linda's amount |
Seth's amount |
Before |
126 u |
140 u |
90 u |
Change |
|
- 77 u (- 55%) |
- 27 u (- 30%) |
After |
|
63 u |
63 u |
Percentage of Linda's amount left
= 100% - 55%
= 45%
Percentage of Seth's amount left
= 100% - 30%
= 70%
45% =
45100 =
920 70% =
70100 =
710 The amounts of amount that Linda and Seth had left were the same.
Make the numerators the same.
920 of Linda's amount =
710 of Seth's amount
63140 of Linda's amount =
6390 of Seth's amount
Amount that Linda had = 140 u
90% of the amount that Linda had
= 140 u x 90%
= 140 u x
90100 = 126 u
Difference between 90% of Linda's amount and Seth's amount
= 126 u - 90 u
= 36 u
36 u = 468
1 u = 468 ÷ 36 = 13
Amount that Seth had at first
= 90 u
= 90 x 13
= $1170
Answer(s): $1170