80% of Xylia's amount was $576 more than Brandon's amount. When Xylia spent 60% of her amount and Brandon spent 10% of his amount, they had the same amount of amount left. Find the amount that Brandon had at first.
|
80% of Xylia's amount |
Xylia's amount |
Brandon's amount |
Before |
36 u |
45 u |
20 u |
Change |
|
- 27 u (- 60%) |
- 2 u (- 10%) |
After |
|
18 u |
18 u |
Percentage of Xylia's amount left
= 100% - 60%
= 40%
Percentage of Brandon's amount left
= 100% - 10%
= 90%
40% =
40100 =
25 90% =
90100 =
910 The amounts of amount that Xylia and Brandon had left were the same.
Make the numerators the same.
25 of Xylia's amount =
910 of Brandon's amount
1845 of Xylia's amount =
1820 of Brandon's amount
Amount that Xylia had = 45 u
80% of the amount that Xylia had
= 45 u x 80%
= 45 u x
80100 = 36 u
Difference between 80% of Xylia's amount and Brandon's amount
= 36 u - 20 u
= 16 u
16 u = 576
1 u = 576 ÷ 16 = 36
Amount that Brandon had at first
= 20 u
= 20 x 36
= $720
Answer(s): $720