A bag consists of a number of 10-cent and 50-cent coins. There are 70% as many 10-cent coins as 50-cent coins. How much money is there in the bag if there are 30 more 50-cent coins than 10-cent coins?
70% =
70100 =
710
| 10-cent |
50-cent |
Difference |
| 7 u |
10 u |
3 u |
Number of 10-cent coins = 7 u
Number of 50-cent coins = 10 u
Difference in the number of coins = 10 u - 7 u = 3 u
3 u = 30
1 u = 30 ÷ 3 = 10
Number of 50-cent coins
= 10 u
= 10 x 10
= 100
Number of 10-cent coins
= 7 u
= 7 x 10
= 70
Amount of money in the bag
= 70 x 0.10 + 100 x 0.50
= 7 + 50
= $57
Answer(s): $57
